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- Technical Information
- Reference
- Formulas for Cutting

CUTTING SPEED (vc)

- vc (SFM)
- :Cutting Speed
- Dm (inch)
- :Workpiece Diameter
- π (3.14)
- :Pi
- n (min
^{-1}) - :Main Axis Spindle Speed

What is the cutting speed when main axis spindle speed is 700 min

Substitute π=3.14, Dm=2, n=700 into the formulae.

vc=π× Dm×n÷12=3.14×2×700÷12=366.33SFM

FEED(f)

- f (IPR)
- :Feed per Revolution
- I (inch/min)
- :Cutting Length per Min.
- n (min
^{-1}) - :Main Axis Spindle Speed

**(Problem):**

What is the feed per revolution when main axis spindle speed is 500min^{-1} and cutting length per minute is 120 mm/min?

**(Answer):**

Substitute n=500, I=4.72 into the formulae.

f=I÷n=4.72÷500=.009IPR

**The answer is .009IPR.**

CUTTING TIME (Tc)

- Tc (min)
- :Cutting Time
- Im (inch)
- :Workpiece Length
- I (inch/min)
- :Cutting Length per Min.

What is the cutting time when 4inch workpiece is machined at 1000min

First, calculate the cutting length per min. from the feed and spindle speed.

I=f×n=.008×1000=8inch/min

Substitute the answer above into the formulae.

Tc=Im÷I=4÷8=0.5min

0.5x60=30(sec.)

THEORETICAL FINISHED SURFACE ROUGHNESS (h)

- h (μinch)
- :Finished Surface Roughness
- f (IPR)
- :Feed per Revolution
- Re (inch)
- :Insert Corner Radius

What is the theoretical finished surface roughness when the insert corner radius is .031inch and feed is .008 IPR ?

Substitute f=.008IPR,Re=.031 into the formulae.

h =(.008)

CUTTING SPEED (Pc)

*Divide by 1000 to change to m from mm.

- vc (m/min)
- Cutting speed
- Dm (mm)
- Workpiece Diameter
- π (3.14)
- Pi
- n (min
^{-1}) - Main Axis Spindle Speed

(Problem)

What is the cutting speed when main axis spindle speed is 700min^{-1} and external diameter is Ø50? Substitute π=3.14, Dm=50, n=700 into the formula.

(Answer)

Substitute π =3.14, Dm=50, n=700 into the formula.

**vc=(π×Dm×n)÷1000=(3.14×50×700)÷1000 =110 (m/min)**

Cutting speed is 110 m/min.

What is the cutting speed when main axis spindle speed is 700min

(Answer)

Substitute π =3.14, Dm=50, n=700 into the formula.

Cutting speed is 110 m/min.

FEED (f)

- f (mm/rev.)
- Feed per revolution
- l (mm/min)
- Cutting length per Min
- n (min
^{-1}) - Main Axis Spindle Speed

(Problem)

What is the feed per revolution when main axis spindle speed is 500min^{-1} and cutting length per minute is 120mm/min ?

(Answer)

Substitute n=500, I=120 into the formula.**f=l÷n=120÷500=0.24 (mm/rev)**

The answer is 0.24 mm/rev.

What is the feed per revolution when main axis spindle speed is 500min

(Answer)

Substitute n=500, I=120 into the formula.

The answer is 0.24 mm/rev.

CUTTING TIME (Tc)

- Tc (min.)
- Cutting Time
- lm (mm)
- Workpiece Length
- l (mm/min)
- Cutting Length per Min.

(Problem)

What is the cutting time when 100mm workpiece is machined at 1,000min^{-1}, with feed=0.2mm/rev?

(Answer)

First, calculate the cutting length per min. from the feed and spindle speed.
**l=f×n=0.2×1000=200(mm/min)**

Substitute the answer above into the formulae.

**Tc=lm÷l=100÷200=0.5(min)**

0.5×60=30(sec.) The answer is 30 seconds.

What is the cutting time when 100mm workpiece is machined at 1,000min

(Answer)

First, calculate the cutting length per min. from the feed and spindle speed.

Substitute the answer above into the formulae.

0.5×60=30(sec.) The answer is 30 seconds.

THEORETICAL FINISHED SURFACE ROUGHNESS (h)

- h (µm)
- Finished Surface Roughness
- f (mm/rev.)
- Feed per Revolution
- Re (mm)
- Insert Corner Radius

(Problem)

What is the theoretical finished surface roughness when the insert corner radius is 0.8mm and feed is 0.2 mm/rev ?

(Answer)

Substitute f=0.2 mm/rev, R=0.8 into the formulae.

**h=f**^{2}÷(8×Re)×1000=0.2^{2}÷(8×0.8)×1000=6.25µm

The theoretical finished surface roughness is 6 µm.

What is the theoretical finished surface roughness when the insert corner radius is 0.8mm and feed is 0.2 mm/rev ?

(Answer)

Substitute f=0.2 mm/rev, R=0.8 into the formulae.

The theoretical finished surface roughness is 6 µm.