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- Technical Information
- Reference
- Formulas for Drilling

CUTTING SPEED (vc)

- vc (SFM)
- :Cutting Speed
- D1 (inch)
- :Drill Diameter
- π(3.14)
- :Circular Constant
- n (min
^{-1}) - :Rotational Speed of the Main Spindle

*Unit transformation (from "mm" to "m")

**(Problem) :**

What is the cutting speed when main axis spindle speed is 1350min^{-1} and drill diameter is .500inch ?

**(Answer):**

Substitute π=3.14, D1=.500inch, n=1350 into the formulae

vc=π× D1×n÷12=3.14×.500×1350÷12=176.6SFM

**The cutting speed is176.6SFM. **

What is the cutting speed when main axis spindle speed is 1350min

Substitute π=3.14, D1=.500inch, n=1350 into the formulae

vc=π× D1×n÷12=3.14×.500×1350÷12=176.6SFM

FEED OF THE MAIN SPINDLE (vf)

- vf (inch/min)
- :Feed Speed of the Main Spindle (Z axis)
- fr (IPR)
- :Feed per Revolution
- n (min
^{-1}) - :Rotational Speed of the Main Spindle

What is the spindle feed (vf) when feed per revolution is .008IPR and main axis spindle speed is 1350min

Substitute fr=.008, n=1350 into the formulae

vf = fr×n = .008×1350 = 10.8inch/min

DRILLING TIME (Tc)

- Tc (min)
- :Drilling Time
- n (min
^{-1}) - :Spindle Speed
- ld (inch)
- :Hole Depth
- fr (IPR)
- :Feed per Revolution
- i
- :Number of Holes

What is the drilling time required for drilling a 1.2inch length hole in alloy steel at a cutting speed of 165SFM and feed .006IPR ?

Spindle Speed n =(165×12)÷ (.59×3.14) = 1068.8min

Tc =(1.2×1)÷ (1068.8×.006) = .187

= .187×60≒11.2 sec

CUTTING SPEED (vc)

*Unit transformation (from "mm" to "m")

- vc (m/min)
- Cutting Speed
- D1 (mm)
- Drill Diameter
- π (3.14)
- Pi
- n (min
^{-1}) - Rotational Speed of the Main Spindle

(Problem)

What is the cutting speed when main axis spindle speed is 1350min^{-1} and
drill diameter is 12mm ?

(Answer)

Substitute π =3.14, D1=12,n=1350 into the formulae

**vc =(π ×D1×n)÷1000 =(3.14×12×1350)÷1000=50.9m/min**

The cutting speed is 50.9m/min.

What is the cutting speed when main axis spindle speed is 1350min

(Answer)

Substitute π =3.14, D1=12,n=1350 into the formulae

The cutting speed is 50.9m/min.

FEED OF THE MAIN SPINDLE (vf)

- vf(mm/min)
- Feed Speed of the Main Spindle(Z axis)
- f (mm/rev)
- Feed per Revolution
- n (min
^{-1}) - Rotational Speed of the Main Spindle

(Problem)

What is the spindle feed (vf) when feed per revolution is 0.2mm/rev and main axis spindle speed is 1350min^{-1}?

(Answer)

Substitute f=0.2, n=1350 into the formulae
**vf = f×n = 0.2×1350 = 270mm/min**

The spindle feed is 270mm/min

What is the spindle feed (vf) when feed per revolution is 0.2mm/rev and main axis spindle speed is 1350min

(Answer)

Substitute f=0.2, n=1350 into the formulae

DRILLING TIME (Tc)

- Tc (min)
- Drilling Time
- n (min
^{-1}) - Spindle Speed
- ld (mm)
- Hole Depth
- f (mm/rev)
- Feed per Revolution
- i
- Number of Holes

(Problem)

What is the drilling time required for drilling a 30mm length hole in alloy steel at a cutting speed of 50m/min and feed 0.15mm/rev ?

(Answer)

Spindle Speed

**n=(50×1000)÷(15×3.14)=1061.57min**^{-1}

Tc=(30×1)÷(1061.57×0.15)=0.188

=0.188×60=11.3sec.

What is the drilling time required for drilling a 30mm length hole in alloy steel at a cutting speed of 50m/min and feed 0.15mm/rev ?

(Answer)

Spindle Speed

Tc=(30×1)÷(1061.57×0.15)=0.188

=0.188×60=11.3sec.