FORMULAS FOR CUTTING POWER
CUTTING SPEED (vc)
- vc(m/min)
- :Cutting Speed
- Dm (mm)
- :Workpiece Diameter
- π (3.14)
- :Pi
- n (min-1)
- :Main Axis Spindle Speed
(Problem) :
What is the cutting speed when n= 700 min-1, and the external diameter
is ø50?
(Answer):
Substituting p=3.14, Dm=50 and n=700 into the
formula.
vc=(p×Dm×n)÷1000=(3.14×50×700)÷1000
=110 (m/min)
Cutting speed is 110 m/min.
FEED (f)
- f (mm/rev)
- :Feed per Revolution
- I (mm/min)
- :Cutting Length per Min.
- n (min-1)
- :Main Axis Spindle Speed
(Problem) :
What is the feed per revolution when n=500 min-1, and the cutting length
per minute is 120 mm/min.
(Answer):
Substitute n=500 and l=120 into the formula
f=l÷n=120÷500=0.24 (mm/rev)
The answer is 0.24 mm/rev.
CUTTING TIME (Tc)
- Tc (min)
- :Cutting Time
- Im (mm)
- :Workpiece Length
- I (mm/min)
- :Cutting Length per Min.
(Problem) :
What is the cutting time when 100mm workpiece is machined at 1,000min-1,
with feed=0.2mm/rev?
(Answer)
First, calculate the cutting length per minute from the feed and the spindle speed.
l=f×n=0.2×1000=200(mm/min)
Substitute the answer above into the formula.
Tc=lm÷l=100÷200=0.5(min)
0.5×60=30(sec) The answer is 30 seconds.
THEORETICAL FINISHED SURFACE ROUGHNESS (h)
- h (μm)
- :Finished Surface Roughness
- f (mm/rev)
- :Feed per Revolution
- Re (mm)
- :Insert Corner Radius
(Problem) :
What is the theoretical finished surface roughness when the insert corner radius
is 0.8 mm and feed=0.2mm/rev?
(Answer):
Substituting f=0.2 mm/rev, R=0.8 mm into the formula.
h=f2÷(8×R)×1000=0.22÷(8×0.8)×1000=6.25µm
The theoretical finished surface roughness is 6 µm.