(Problem) :
What is the cutting speed when main axis spindle speed is 700 min-1 and external diameter is φ2" ?
(Answer):
Substitute π=3.14, Dm=2, n=700 into the formulae.
vc=π× Dm×n÷12=3.14×2×700÷12=366.33SFM Cutting speed is 366.33SFM.
FEED(f)
f (IPR):Feed per Revolution I (inch/min):Cutting Length per Min. n (min-1):Main Axis Spindle Speed
(Problem):
What is the feed per revolution when main axis spindle speed is 500min-1and cutting length per minute is 120 mm/min?
(Answer):
Substitute n=500, I=4.72 into the formulae.
f=I÷n=4.72÷500=.009IPR The answer is .009IPR.
CUTTING TIME (Tc)
Tc (min):Cutting Time Im (inch):Workpiece Length I (inch/min):Cutting Length per Min.
(Problem):
What is the cutting time when 4inch workpiece is machined at 1000min-1 with feed= .008IPR ?
(Answer):
First, calculate the cutting length per min. from the feed and spindle speed.
I=f×n=.008×1000=8inch/min
Substitute the answer above into the formulae.
Tc=Im÷I=4÷8=0.5min
0.5x60=30(sec.)The answer is 30 sec.
THEORETICAL FINISHED SURFACE ROUGHNESS (h)
h (μinch):Finished Surface Roughness f (IPR):Feed per Revolution Re (inch):Insert Corner Radius
(Problem):
What is the theoretical finished surface roughness when the insert corner radius is .031inch and feed is .008 IPR ?
(Answer):
Substitute f=.008IPR,R=.031 into the formulae.
h =(.008)2÷(8×.031)×10002=258μinch
The theoretical finished surface roughness is .258μinch.