FORMULAS FOR DRILLING
CUTTING SPEED (vc)
- vc (SFM)
- :Cutting Speed
- D1 (inch)
- :Drill Diameter
- π(3.14)
- :Circular Constant
- n (min-1)
- :Rotational Speed of the Main Spindle
*Unit transformation (from "mm" to "m")
(Problem) :
What is the cutting speed when main axis spindle speed is 1350min-1 and drill diameter is .500inch ?
(Answer):
Substitute π=3.14, D1=.500inch, n=1350 into the formulae
vc=π× D1×n÷12=3.14×.500×1350÷12=176.6SFM
The cutting speed is176.6SFM.
FEED OF THE MAIN SPINDLE (vf)
- vf (inch/min)
- :Feed Speed of the Main Spindle (Z axis)
- fr (IPR)
- :Feed per Revolution
- n (min-1)
- :Rotational Speed of the Main Spindle
(Problem):
What is the spindle feed (vf) when feed per revolution is .008IPR and main axis spindle speed is 1350min-1?
(Answer):
Substitute fr=.008, n=1350 into the formulae
vf = fr×n = .008×1350 = 10.8inch/min
The spindle feed is 10.8inch/min.
DRILLING TIME (Tc)
- Tc (min)
- :Drilling Time
- n (min-1)
- :Spindle Speed
- ld (inch)
- :Hole Depth
- fr (IPR)
- :Feed per Revolution
- i
- :Number of Holes
(Problem):
What is the drilling time required for drilling a 1.2inch length hole in alloy steel at a cutting speed of 165SFM and feed .006IPR ?
(Answer):
Spindle Speed n =(165×12)÷ (.59×3.14) = 1068.8min-1
Tc =(1.2×1)÷ (1068.8×.006) = .187
= .187×60≒11.2 sec